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A-level Chemistry Year 12 · Topic 8

Required and core practicals

Required and core practicals are the experiments every A-level chemist must be able to describe, carry out and analyse.

We will make a standard solution and carry out a titration, measure the molar volume of a gas, and find enthalpy changes by calorimetry.

Then we investigate rates of reaction, prepare an organic liquid by reflux and distillation, and purify it with a separating funnel, drying agent and redistillation.

In this topic

  1. 8.1Practical: preparing a standard solution and carrying out an acid-base titrationFree below · 67 questions
  2. 8.2Practical: measuring the molar volume of a gas and determining moles from reacting massesOpen in Full Marks · 66 questions
  3. 8.3Practical: measuring enthalpy changes by calorimetry (neutralisation, displacement, solution and combustion)Open in Full Marks · 65 questions
  4. 8.4Practical: investigating rates of reaction by gas collection, clock reactions and continuous monitoringOpen in Full Marks · 72 questions
  5. 8.5Practical: preparing an organic liquid by heating under reflux and distillation (e.g. oxidation of an alcohol)Open in Full Marks · 62 questions
  6. 8.6Practical: purifying an organic liquid using a separating funnel, drying agent and redistillationOpen in Full Marks · 34 questions

8.1 · Free notes

Practical: preparing a standard solution and carrying out an acid-base titration

Diagram: Practical: preparing a standard solution and carrying out an acid-base titration

Key points

In more detail

Practice

Practical: preparing a standard solution and carrying out an acid-base titration: 10 questions

Pick an answer to check it, or open the answer for the explanation.

1. 25.0 cm³ of aqueous NaOH needs a mean titre of 22.50 cm³ of 0.100 mol dm⁻³ HCl for neutralisation. What is the concentration of the NaOH?

  1. 0.0225 mol dm⁻³
  2. 0.111 mol dm⁻³
  3. 0.900 mol dm⁻³
  4. 0.0900 mol dm⁻³
Show answer

D: 0.0900 mol dm⁻³. n(HCl) = 0.100 × 0.02250 = 2.25 × 10⁻³ mol. The ratio is 1:1, so n(NaOH) is the same. c = 2.25 × 10⁻³ ÷ 0.0250 dm³ = 0.0900 mol dm⁻³.

2. 20.0 cm³ of 0.150 mol dm⁻³ H₂SO₄ is neutralised by 0.200 mol dm⁻³ NaOH. What volume of NaOH is needed?

  1. 15.0 cm³
  2. 30.0 cm³
  3. 60.0 cm³
  4. 10.0 cm³
Show answer

B: 30.0 cm³. n(H₂SO₄) = 0.150 × 0.0200 = 3.00 × 10⁻³ mol. The ratio is 1:2, so n(NaOH) = 6.00 × 10⁻³ mol. V = 6.00 × 10⁻³ ÷ 0.200 = 0.0300 dm³ = 30.0 cm³.

3. What mass of anhydrous Na₂CO₃ (Mr = 106.0) is needed to make 250.0 cm³ of a 0.0400 mol dm⁻³ standard solution?

  1. 1.06 g
  2. 10.6 g
  3. 4.24 g
  4. 0.530 g
Show answer

A: 1.06 g. n = 0.0400 × 0.2500 = 0.0100 mol. Mass = n × Mr = 0.0100 × 106.0 = 1.06 g.

4. Which indicator is most suitable for titrating ethanoic acid with sodium hydroxide solution?

  1. Litmus
  2. Universal indicator
  3. Phenolphthalein
  4. Methyl orange
Show answer

C: Phenolphthalein. Weak acid–strong base: the equivalence point is above pH 7. Phenolphthalein (pH range about 8.3–10) changes sharply there. Universal indicator and litmus do not give sharp end-points.

5. Burette readings have an uncertainty of ±0.05 cm³ each. What is the percentage uncertainty in a titre of 24.00 cm³ (two readings)?

  1. 0.10%
  2. 0.21%
  3. 2.1%
  4. 0.42%
Show answer

D: 0.42%. A titre uses two readings, so the uncertainty is ±0.10 cm³. Percentage uncertainty = 0.10 ÷ 24.00 × 100 = 0.42%.

6. Titres are: rough 24.60, then 23.60, 23.30 and 23.40 cm³. Using concordant results only (within 0.10 cm³), what is the mean titre?

  1. 23.43 cm³
  2. 23.73 cm³
  3. 23.35 cm³
  4. 23.30 cm³
Show answer

C: 23.35 cm³. Only 23.30 and 23.40 are within 0.10 cm³ of each other. The rough titre and 23.60 are excluded. Mean = (23.30 + 23.40) ÷ 2 = 23.35 cm³.

7. Why must a burette be rinsed with the solution it will contain before filling?

  1. To remove air bubbles from the tap
  2. To calibrate the volume markings
  3. To warm the solution to room temperature
  4. Water left in it would dilute the titrant
Show answer

D: Water left in it would dilute the titrant. Residual distilled water would dilute the titrant, lowering its concentration. A larger titre would then be needed and the calculated result would be wrong.

8. An air bubble in the burette jet is expelled during a titration. What is the effect on the recorded titre?

  1. No effect on the titre
  2. Titre too small
  3. Titre too large
  4. The effect cannot be predicted
Show answer

C: Titre too large. The fall in burette reading includes the volume that filled the space left by the bubble. This volume was not delivered as titrant, so the recorded titre is too large.

9. Why is sodium hydroxide not suitable as a primary standard?

  1. It is a weak base
  2. It absorbs water and CO₂ from air, so its mass is unreliable
  3. Its molar mass is too high
  4. It is insoluble in water
Show answer

B: It absorbs water and CO₂ from air, so its mass is unreliable. NaOH is hygroscopic and reacts with CO₂ in the air, so its purity and weighed mass are uncertain. A primary standard must be pure, stable and non-hygroscopic.

10. Vinegar was diluted tenfold. 25.0 cm³ of the diluted vinegar needed 18.40 cm³ of 0.100 mol dm⁻³ NaOH. What was the original concentration of ethanoic acid?

  1. 1.84 mol dm⁻³
  2. 7.36 mol dm⁻³
  3. 0.736 mol dm⁻³
  4. 0.0736 mol dm⁻³
Show answer

C: 0.736 mol dm⁻³. n(NaOH) = 0.100 × 0.01840 = 1.84 × 10⁻³ mol = n(acid), so the diluted acid is 0.0736 mol dm⁻³. The original is ten times larger: 0.736 mol dm⁻³.

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Full Marks has 67 questions on Practical: preparing a standard solution and carrying out an acid-base titration (57 more than here), set out in practice levels. You also get notes and 3D models for all 6 subtopics of Required and core practicals, plus games, timed exams and past papers.

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